twenty eight is the GCF of 28 and 84.
(69.1 - 52.3)(360) = 6048 miles more
This is not possible you have 1/3 = -3/5 Not true!
63/300 x 100% = 21%
The distance to the flagpole is ONE leg (adjacent) of a right triangle. the OTHER (opposite) leg is the height of the flagpole minus her height. (15 x 12 - 62 = 118 inches)
tan11.3 = opposite/adjacent = 118/ x x = 118/tan11.3 = 590.53 inches = 49.21 feet from the lag pole
You'll have to tell us how many hours the climber was at it.....
From the endpoint to the midpoin x goes from 6 ----> 1 (or -5) move x another -5 to get the other endpoint x = -4
y 0----> 10 (or +10) y 10 y= 20
Other endpoint is thus (-4, 20)
p + 1/6 = 6/11
p = 6/11 - 1/6
p = 36/66 - 11/66 = 25/66
25 minute : 4 hours x 60 minute/hr
25 : 240
5:48
If there is no air friction.....when the rock comes down to its launch point it will be going the same speed as when it was launched, so it will be traveling downward at the same speed as the first rock was thrown (down) and will have the same energy at impact: #2 K joules
