3x + 10 > 5x + 22 subtract 3x from both sides of the inequality
10 > 2x + 22 Subtract 22 from both sides
-12 > 2x Divide by 2
-6 >x or rewritten x < -6
Maybe a little simpler:
Since they gave you the realtive speed as 105 mph and the distance travelled as 95 miles
95 miles/105 mph = .90476 h (as we found starting in 2nd step of prior solution)
Train a travels 45 mph x t
Train b travels d - 60 x t where d = 95 miles (given)
45t = 95-60t
105t = 95
t = 95/105 = .90476 hours (54.2857 minutes)
Check 45 (.90476) + 60(.90476) =? 95
95 = 95 Check!
27 in - 18 in = 9 inches in 10 months 9/10 = .9 inch/month
2182 followed by 297 zeros
Yes. ========> YOU !!
(1/3)^x = .004 take the log of both sidesof the equation to get
x log(1/3) = log (.004)
x = log(.004)/log(1/3) = 5.025
7^k + 10 + 3 = 15 Subtract 13 from both sides of the equation
7^k = 2 Take the LOG of both sides
k log 7 = log 2
k = log 2/ log 7 = .3562
What is your QUESTION? You left off that part !
