ElectricPavlov

Wel-l-l-l  ,  I guess there WASN'T an easier way !  

Draw a line from the center to each of the endpoints of the chord

   this forms a equilateral triangle     the central angle is 60 degrees   (pi/3 radians)

the area of this sector is   60/360 of the TOTAL area of the circle

    pi r^2  x  60/360   = 6 pi

Now subtract the area of the equilateral triangle to get the area enclosed by the chord

  area of equalateral triangle = r^2 (sqrt3) / 4   = 9 sqrt3

6pi - 9 sqrt3 = area of chord

Total area of cicle - area enclosed by chord = larger area

 36 pi      -    ( 6pi  - 9 sqrt3)

30 pi + 9 sqrt3     units²

^{(there has to be a better way! )}

Nope, still not correct     Ooops....  back to the drawing board......

All of the exterior angles of a polygon sum to 360

360/15 = 24 sides

the smallest odd number greater than 7x − 2     will always equal 7x-1

he largest odd number less than 3x + 5                is 3x+3

(7x-1) - (3x+3) = 4x - 4         a = 4 b = - 4         a+ b = 0

You can do these problems very easily yourself,   here is screenshot of your problem solved by Web2 calculator: (even shows your required fraction)

Well  .....just convert it.....you do know how to do that, yah?

-725/1000

-29/40

-0.725    from pasting into the calculator on this site.

[(x-2) + (x) + (x+2)  ]  =  1/7(x-2)(x)(x+2)

3x   = x^3-4x

21 = x^2-4

0 =x^2 -25    x = -5 (throw out) or 5

so the numbers are   5-2 = 3   5   and 5+2 = 7         (as guest posted)

From 4 to 1   is -3    add another -3      for x = -2

From 5 to -2  is -7   add another -7              y = -9