ElectricPavlov

https://web2.0calc.com/questions/can-anyone-please-solve-this-mathematics-question

https://web2.0calc.com/questions/maths-question_22

https://web2.0calc.com/questions/can-anyone-please-solve-this-mathematics-question

10 to 630 = 8 1/2 hours

8 1/2 /24   = 17/48  probability   (?)   

Note: I do not know if this is correct

35 x 10^-6  =  k/ (180^4)      k= 36741.6

Power = 36741.6 / 540⁴ =  432 .09   nanowatts       or         4.32 x 10^-7 watts

(20 p *24 m) / 6000 ft^2   =  .08  p-m / ft²

.08  p-m / ft2  * 8000 ft² / 20 p 

see how things 'cancel out'   and yo are left with minutes?    .08 * 8000 / 20  = 32 minutes

You try the second one......

20 cm³ /min   x 10 min = 200 cm³

 Volume of cylinder =  pi r² h              we are looking for h

    200 cm^3            = pi  5²  h             solve for h    ( remember it is r²    ....and you are given DIAMETER,    r = 1/2 diameter = 5)

I answered this Q the other day, but it may have been incorrect

I believe the sampling frequency to be   2  x  12 khz = 24 khz

to represent 512 levels would require  9 bits :       2^9 = 512

So each of 24000 samples will require an add'l 9 bits      24000 x 9 =   2.16 x 10⁵    bits / s   

First, 15 l is 3.962 gallons needed      or 507.21 oz

He only need 3.962 gallons   so he would best be served by buying  a four gallon  bucket @ $ 6.56

           two 2 gallon buckets   total cost   8.56

           one two and one 3 costs              10.20  

Is Jerry's rate   2 envelopes per minute???

i'll assume jerry can stuff 2 envelopes / min

84 env  /  ( 2 env/min + 3 env/min) = 84/5 = 16.8 mins