ElectricPavlov

The trains are separating at  85 + 95 = 180 m/hr

252 miles/ 180 m/hr = 1.4 hours

The two circular ends will each have the area of the circle    2   x  pi r^2      ft₂            r = 11 ft

the cylindrical sidewall will have an area of  pi d h    ft²         d = 22 ft     h = 35 ft       plug and chug !

535 miles  - 190 miles - 106 miles =  .......   miles on Sunday

L = 12 + 2H

2L + 2H = 264

2(12+2H) + 2H = 264

24 + 6H = 264

H = 40    then L = 12 + 2H = 92

The ONLY answer that has the correct units is A    33.5  in³       No calculation necessary.

y= mx+b      m = slope

y = 1/3 x + b     sustitute in the point given to calc 'b

4 = 1/3 (-3) + b      b =  5

y = 1/3  x + 5

AC || FD    so  angle C = 3x    (=  Angle D)

x + 8x +3x = 180^o      Solve for 'x'

Square area would be   side length x side length      4.5  x 4.5 cm²

    added to triangle area   1/2 bh    =   1/2 (4.5)(4.5) cm²

Use law of cosines to find missing side length

   then use Heron's Rule to calculate the area....

.09 x   +   .13 (80 000 -x)  = 8000

x = 60 000 @ 9%     20 000 @ 13%