1/a + 1/b + 1/c = 1/2
1/6 + 1/4 + 1/c = 1/2 solve for 'c' the time of chad alone
2/12 + 3/12 + 1/c = 1/2
1/c = 1/2 - 5/12
1/c = 1/12
c = 12 hours
c = child tix revenue from = $ 6 c
a = adult tix = 166-c revenue from = $ 9.70(166-c) Summed, the two revenues total 1351,20
6 c + 9.7 (166-c ) = 1351.20 solve for 'c' the number of chlid tix
Wilma (x-1)(x-6) = x^2 -7x + 6 but the '-7' is wrong and the 6 is correct
Greg (x+1)(x+4) = x^2 + 5x + 5 but the c = 5 is wrong
SO the equati0n must be x^2 + 5x + 6 which factors to (x+3)(x+2) roots -3 and -2
They are opposite angles of intersecting lines so they have to equal each other
3x+30 = 2x-80 solve for 'x' then angle 3 = x+30
4+ 7 = 11 the number of students must be a multiple of 11 and between 24-40
33
20 / h = 10 / (36-h) solve for h
I get 136.64 ft
Tan A = opp / adj = 14/7
A = arctan(14/7) = ~ 63o
1 /2 (8)(4) = 16 units2
Randy has a head start 16 m/hr x 4 hr = 64 miles
Jimmy is going 48-16 m/hr faster = 32 m/hr faster
Jimmy will cover the 64 mile headstart and catch Randy after 64 m / 32/mhr = 2 hours
