xf=xi+vit+1/2gt^2 put in the values you are given
xf = 1 + vi t + 1/2 g t^2 ( I think that should be MINUS 1/2 gt^2)
anyway xi is initial position = 1 m (given)
I am a bit confused as to what you ae looking for? You ask for xi and then vi and then xf and you have a t = .01 (what is that?)