Alan

√(10² + 10²) = 10√2

$${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{2}}}} = {\mathtt{14.142\: \!135\: \!623\: \!730\: \!950\: \!5}}$$

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gradient = (y2 - y1)/(x2 - x1)

 here:

$${\mathtt{gradient}} = {\frac{\left({\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{\left({\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0}}\right)}} \Rightarrow {\mathtt{gradient}} = {\mathtt{3}}$$

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I guess exposant means exponent so:

10⁴ = 10000

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heureka is correct.

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Actually, I also solved it algebraically at first, Melody, then realised there was a nice geometric treatment of it.

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Note that heureka's answer and mine are different ways of expressing the same thing because

$$e^{i\theta}=cos\theta+isin\theta$$

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To the nearest hundred this is 9600

To the nearest hundredth it is 9567.81

Look at the tens position (for hundred) or the thousandths position (for hundredths): If that number is less than 5 keep the hundred/hundredths digit the same, otherwise change it to the next higher digit.

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I assume you mean 

$$h(x)=2+3e^{-x-1}$$

in which case:

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Distrubute the 8 over the terms in brackets and collect like terms:

$$9m^6+8(m^6+16)\rightarrow 9m^6+8m^6+8\times16\rightarrow17m^6+128$$

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