Assuming this is
$$6x^{1.7}+4=14$$
subtract 4 from both sides
$$6x^{1.7}=10$$
divide by 6
$$x^{1.7}=\frac{10}{6}$$
Take logs of both sides and use the fact that log(ab) = b*log(a) and log(a/b) = log(a) - log(b)
$$1.7\log{x}=\log{10}-\log{6}$$
divide by 1.7
$$\log{x}=\frac{\log{10}-\log{6}}{1.7}$$
Use the fact that log10a = b means a = 10b
$$x=10^{\frac{\log{10}-\log{6}}{1.7}}$$
and since log1010 = 1
$$x=10^{\frac{1-\log{6}}{1.7}}$$
You can complete the calculation.
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