First, use s = v1t + (1/2)gt2 to find v1, the velocity at s = 1m (g = 9.81 m/s2, t = 0.05 s).
Then use v12= 2gh to find the distance, h, from the top of the bridge to 1 m above the water (assuming rock is dropped with zero initial velocity).
Then height of bridge = h + 1 m