You might have to check this for me. Idk if this is correct:
(1) There are 11 balls in total, with 8 white and 3 red.
First ball: You have a 8/11 chance of the first ball being white, and a 3/11 chance of it being red.
Second ball: This depends on what you drew on the first ball. If you drew a white first, you now have a 7/10 chance of getting white.
Total probability for both white: 8/11 * 7/10 (since both are independent events) = 28/55.
(2) There are 11 balls in total, with 8 white and 3 red.
First ball: You have a 3/11 chance of being red.
Second ball: If you drew red the first time, you now have a 2/10 chance of it being red.
Total probability for both red: 3/11 * 2/10 = 3/55
(3) I don't really know how to do this, can someone solve this?
