AnimalMaster

No problem!

Bunch of typos, we can't help you.

Thank you CPhill!

Let's make Z the price of a zucchini, and Z + 0.25 the price of a kiwi.

We know that 3(Z + 0.25) + 4 * Z = 4.95.

If we simplify the equation: 3Z + 0.75 + 4Z = 4.95.

Subtracting 0.75 from both sides: 7Z = 4.20

Z = 0.6 which is the price of a zucchini

Z + 0.25 = 0.85 which is the price of a kiwi. 

Which is what CPhill got!

How are you getting so many of these questions?

So you have 17 wins and 3 losses which means they played 20 games so far.

The question states that it's only 2/3 of all it's games, which means 20 = 2/3. So that means that they played 30 games in total.

3/4 of 30 is 22.5, but we can round up to 23. So that means the team must win 23 games, and lose at MOST 7 games. It already lost 3 games so 7 - 3 = 4.

The remaining games that the team can still lose is 4 games.

Well, I don't really know this but I'll give it a shot:

We need to caculate the amount of ways from (0,0) to (5,7): 12C5=792 ways from (0,0) to (5,7), and then subtract that by the amount of ways that pass the spider.

Next, we also need to caculate the paths from (0,0) to (4,3) and multiply that by the amount of paths from (4,3) to (5,7):

7C3 * 5C1 = 175.

792 - 175 = 617.

Nope! You're correct! Thanks Melody!

Well, we know we can split the balls into four groups: 4-0-0-0, 3-1-0-0, 2-2-0-0, 2-1-1-0, 1-1-1-1.

Case 1: 4-0-0-0 has only 1 way we can assign the balls to different boxes.

Case 2: 3-1-0-0 has (I think) 4 ways we can assign the balls to different boxes. The one ball can go anywhere, and the three other balls must go in a different box

Case 3: 2-2-0-0 has 4C2 = 6 ways to choose two balls to go in one box, then the other two balls must go in separate boxes. But since order doesn't matter, (there is no first box or second box), we divide by 2.

Case 4: 2-1-1-0 has (again) 4C2 = 6 ways to choose two balls to go in one box, then the other balls go in seperate boxes.

Case 5: 1-1-1-1 has only 1 way.

1 + 4 + 6/2 + 6 + 1 = 15.

Please check for me.

So I'm not gonna give you the answer here (because I haven't calculated it yet), but in these types of problems, I think you should use a Venn diagram.

Make three circles and label them for Football, basketball, and baseball. Where all three circles overlap, put the number 36 in it. And put 128, 291, and 318. The reason that the sum of these numbers goes over 427, is because some of these people play other sports or all 3 sports.

Yeah, I checked at the one that geno3141 answered, and it seemed right and I understood the solution, but for some reason it's incorrect. I tried doing it again using his way and multiplied the fractions and got 64/405 but it was still incorrect.

So I'm not really sure about that problem.