AnimalMaster

If x does not mean multiplication, this question does not make sense.

IF it DOES mean multiplication:

4 * 7 * 087 * 37 * 6 * 5 * 3 * 76 * 545 * 674 * 334 * 666 * 666 * 443 = number too big to calculate.

1) Without any restrictions, there are 18*17*16 = 4896 ways  that three people can be seated. Then, we have to subtract  the cases where they are adjacent.

Case 1: Where all three people are next to each other in a "boomerang" shape. There are 18 ways to choose three consecutive seats. There are then 3! = 6 ways to place those three people, which gives us 18*6=108 possible seatings where they are next to each other.

Case 2:  There are two people sitting next to each other, and the third person is not next to either of them (loner, like me).

There are 18 ways to choose two consecutive seats for the two people. There are then 14 ways to choose the third seat for the loner. After the three seats have been chosen, there are 3!=6 ways to place the three people, which gives us 18*14*6=1512 possible seatings.

Subtracting all of them: 4896-1512-108=3276 ways.

Hope this is right!

2) Can't help you since there is a typo. "After  steps". No number.

Awww, thank you!

Are we really supposed to be helping you on a test??

Ohhh.

Well, we can multiply 40 green cars by 3 to even the ratio out so it's 3 to 3.

So that means there are 120 cars in order to be 3 to 3, which means 120 silver cars.

Subtracted 20 from 120 = 100  because 20 silver cars. So that means there are 100 silver cars.

Isn't it 0? 2 ducks, take away two ducks. 0 ducks?

Uhh... if you take 2 and there are 2 on the counter.

You have 0 left?

How are you getting all these questions?????

Well, there are 7C1 = 7 ways for the chairmen.

6C2 = 15 ways to choose two deputies (2 deputies out of 6 remaining people).

4C2 = 6 ways to choose two assistants (2 assistants out of 4 remaining people)

Multiplying them: 15*6*7 = 630 different ways.