AnswerMachine

This is the collection of all points $x$ that satisfy $x \leq -4$ or $3 \leq x < 5$. These intervals are $(-\infty, -4]$ and $[3, 5)$, so the entire collection of points is $\boxed{(-\infty, -4] \cup [3, 5)}$.

Dude if you REALLY want the answer JUST SEARCH IT UP ON GOOGLE AND YOU WILL FIND MANY ANSWERS (though most of them are wrong)

This is very easy...

We have $f(3) = 12(3)^9 + 3$ and $f(-3) = 12(-3)^9 + (-3)$. Adding, this is $12(3)^9 + 3 + 12(-3)^9 + (-3)$. Since $(-1)^9 = -1$, this simplifies as $12(3)^9 + 3 - 12(3)^9 - 3 = \boxed{0}$.

Yes! you too

144 hectares a day

10 seconds

great job guest!

Yeah I think that is the correct solution asinus

to the nearest hundredth then it would be 10.67 

If you mean QM's question then the answer would be 10 2/3

AE is 4 so -AE=-4

You know it's best not to assume.

I'm sorry guest but thet is wrong

Let $s$ and $\ell$ be the shorter and longer of the remaining sides of the triangle. We are told that $25+s+\ell=80$. By the Triangle Inequality,$$s+25>\ell.$$Adding $\ell$ to both sides of the inequality gives \begin{align*} s+25+\ell &> 2\ell \\ 80 &> 2\ell, \end{align*}so the largest value of $\ell$ is $39$. In that case, $s=80-(25+\ell)=80-64=\boxed{16}$.