Hmmmm I vote bestzack66. But I'm still not sure.
Henlo! And no, don't bow down to me, I did NOT score a perfect on the IMO, I'm not even close to qualifying to IMO!
I wonder who you are
Nice answer, by the way!
Dollars? 1.05? I think that is far too small... and the answer shouldn't be in dollars. Were you trying to latex the solution?
I think you made a typo :)
The answer is 4x^2+2/3x+1/36, not 3x^2+2/3x+1/36
(Latexed)
\((2x+\frac{1}{6})(2x+\frac{1}{6})\)
Multiply
\(4x^2+\frac{2}{3}x+\frac{1}{36}\)
Annnd that's your answer!
Take out 2020^2019
\(\frac{2020^{2019}(2020^2-1)}{2020^{2019}(2020^1-1)}\)
Erase the 2020^2019
\(\frac{2020^2-1}{2020^1-1}\)
Which is 2021
Um I'd appreciate it if you DIDN'T answer horribly to our questions, so I'll just answer this.
1.32 times 10^7 is 13200000
2 times 10^-2 is 0.02.
13200000/0.02 is 660000000
Done! :)
Oops I am late, too! Same to you!