If it is parallel to the line y = 5x + 7, the line will have a formula of y = 5x + a
(7) = 5(-5) + a
Find a.
=^._.^=
y = k x^(1/4)
Let's start by finding k.
3sqrt(2) = k * (81)^(1/4)
3sqrt(2) = k * 3
k = sqrt(2)
y = sqrt(2) * 4^(1/4)
Can you take it from here? :))
Happy birthday Rosala. :))
Try drawing out the two triangles out and testing each of the cases to see if they're true.
Remember that angle R = angle X, angle S = angle Y, and angle T = angle Z.
(a - 1/a) = 2 (note that normally we couldn't assume that it isn't -2, but since a > 1, a - 1/a has to be positive.
(a - 1/a)^3 = 8
a^3 - 3a + 3/a - 1/a^3 = 8
a^3 - 1/a^3 - 3(a - 1/a) = 8
Can you figure it out from here?
Let a, b, c be the three non negative integer sides of the triangle, where a <= b <= c.
The triangular inequality tells us that a + b > c.
List out the possible a, b, and c sides. :))
Yep, you could also first subtract the quadratic solutions, from the quadratic equation. :))
(-b+sqrt(b^2 - 4ac))/2a - (-b-sqrt(b^2 - 4ac))/2a
sqrt(b^2 - 4ac)/a
Remember that we're looking for the positive difference.
Using vieta's, a + b + c = -(-121)/24 = 121/24.
Can you take it from here?
Is there some more information?
Maybe an equal sign?
Nice solution. :))
Another method to use would be the binomial theorem.
(2x)^4*(4)^2*6C4 = 3840x^4
