Ohh, nice job. :))
=^._.^=
Which one did you try?
Good luck. :))))
We're going to complete the square. :))
h(t) = -15t^2 + 45t + 10
h(t) = -15(t-1.5)^2+ 43.75
A square minumn is 0, and we want the (t-1.5)^2 to be as small as possible, so it's 0.
h(t) = -15*0+ 43.75
h(t) = 43.75
Our maximum height is 43.75
Have fun. :))
They are incredibly frustrating, just remember to use google.
Google is your best friend.
x intercepts are when y = 0.
f(-4) = 0
f(2) = 0
So f(4-8) = f(-4) = 0
f(6-8) = f(-2) = 0
So our answers is 4 and 6
I hoep this helped. :))
Hewo, welcome to web2.0 calc. :)))
The change of them both happening is 1/3*2/7 = 2/21
I hope this helped. :))
Since the smaller traignle side length is 1/3 of the large one, x should be 6*1/3 = 2.
Corresponding angles are the same in similar tirangles, so y should be 30 degrees.
Hope this helped. :))
You could list out th epossibilities, or you can use stars and bars.
(6+2)C(3-1) = 8C2 = 8*7/2 = 28.
