catmg

(x^2 - 81)^2 = 324

x^2 - 81 = 17

x^2 = 98

x = +-sqrt(98)

x^2 - 81 = -17 

x^2 = 64

x = +- 8

=^._.^=

f(12) = -13/11

g(-13/11) = 22

f(22) = -23/21

g(23/21) = 21. 

So it looks like each round it subtracts 1. 23 - 8 = 15

=^._.^=

7^2*pi - 4^2*pi is question 11 because you're subtracting the small white circle from the large circle. 

14*28 - 14^2*pi/2 is question 12 because you're subtracting the half circle from the rectangle. 

Nice job. :))

=^._.^=

That's cool. 

I saw the pattern, but had no idea how to write it into a function. 

=^._.^=

80% = .8

.8 * 30 = 24

=^._.^=

Oh oops, I didn't realize it was a different problem. 

But the same solutions still apply. :))

Distance formula is so smart. 

=^._.^=

I just thought of a nice different solution, so I'll post it here. :))

I'm going to refrence Melody's graph since I'm not sure how to make my own yet. 

Note than if you split this triangle in half, you get a 3, 4, 5 traingle. 

Let's call the radius r. 

The point (3, 4) a. 

The point (0, 0) b. 

The point (6, 0) c. 

The point (3, 0) d. 

And the center C. 

Since aC = r, Cd = 4 - r. 

bC = r too. 

ad = 3. 

By pythagreon

(4-r)^2 + 3^2 = r^2

r^2 - 8r + 16 + 9 = r^2

8r = 25

r = 25/8

=^._.^=

Melody, CPhill, and Tigsy already did an amazing job answering this problem. :))

https://web2.0calc.com/questions/math_51432

=^._.^=

5000/131 = 38 and a bit more

N = 131x + 11 

x can be from 0 to 38, 39 answers. :))

=^._.^=