catmg

Thank you. :))

I learnt it from an amc problem. 

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2/3 of the numbers will not be multiples of 3, and 3/4 of the numbers won't be multiples of 4. 

1200 * 2/3 * 3/4 = 600

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Probability is the chance that something will happen. 

The chance of me flipping a head is 1/2, 50% chance of happening. 

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Oops, I forgot to multiply a 2. 

850 * 2 * 2 * 2

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5/7 * 4/6 * 3/5. 

At first person she picks has 5/7 chance of being a girl, then 4/6, then 3/5. 

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The deminsions are 2 times the smaller bucket. 

Volume is 3 deminsions, so 850 * 2 * 2.

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Oops, I meant 34 not 37. 

13+34 = 47. 

Thank you for noticing. 

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Looking at this problem, the first thing that I notice is that 13 + 37 = 47. 

34 = -13 (mod 47)

13^(-1) = 29 (mod 47)

-13^(-1) = -29 (mod 47)

-29 = 18 (mod 47)

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12 players, how many pairs of people can we get?

12*11/2 = 66

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There are 2 cases for this (negative, negative, positive) or (positive, positive, negative). 

For this problem, order doesn't matter. 

negative, negative, positive

a and b are negative, and c is positive. 

a/|a| would be -1 since a is negative. 

b/|b| would be -1 since b is negative. 

c/|c| would be 1 since c is positive. 

abc/|abc| would be 1, since negative * negative * positive is positive. 

-1 - 1 + 1 + 1 = 0

positive, positive, negative

a and b are positive, and c is negative. 

a/|a| would be 1 since a is positive. 

b/|b| would be 1 since b is positive. 

c/|c| would be -1 since c is negative. 

abc/|abc| would be -1, since positive * positive * negative is negative. 

1 + 1 - 1 - 1 = 0

So I think there is only one value, 0. 

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