CPhill

m + (-8) = 2 

m - 8 = 2     add 8 to both sides

m = 10

Let's say the vector is <x, y >

The direction [ reference angle]   is given by :

tan^-1 (y / x)  = theta

Be aware that the signs  on the components  will tell you in what quadrant the vector will lie

.4x-6=36    add 6 to both sides

.4x = 40    divide both sides by .4

x = 40 / .4 =    100

 (x - 3) 2 = 5   simplify

3x - 6   = 5      add 6 to both sides

3x = 11   divide both sides by 3

x = 11 / 3

rational = can be expressed as a fraction   ex:  4/5, 2/3  etc.

irrational  = cannot be expressed as a ratio [fraction]     ex: sqrt(13), pi, "e"  etc.

If something is 20% off....it must be worth only 80%  of what it was originally....so we have

29.99 * .80   =   about $24   [the price has been reduced by about $6]

If 40% of the 80 students are girls.....then there are .40 * 80  = 32 girls

And if the number of girls increased by 60%  we would have  32(1 + .60)  = 51.2  girls.....!!!

If you meant that the percent of girls increased to 60%, then Rosala's answer of 48 is correct

Very nice, Omi67......!!!!

(104e^(−r*1.5))=96-7.396      simplify

104e^(-1,5r)  = 88.604     divide both sides by 104

e^(-1.5r)  = 88.604/104      take the ln of both sides

ln e^(-1.5r) = ln (88.604/104)    and we can write

(-1.5r)lne  = ln(88.604/104)     and ln e = 1  so we can ignore this

(-1.5r)  = ln(88.604/104)     divide both sides by -1.5

r = ln(88.604/104)/( -1.5)  ≈  0 .106809

The slope of a street is 0.54. If it covers 28 metres of horizontal distance, what is the rise of the street?

This means that for every 1 m change in horizontal distance, the street rises .54m

[Note that when  the slope is just given as a single number, we can put that number over 1.....so here....  0.54   = 0.54 / 1       .....and that's the slope ]

So........28(.54)  = 15.12 m   is the rise

[Unfortunately your pictures don't post ]