Here it is
The perimeter is given by
P = 2 ( W + L)
P / 2 = W + L ⇒ P/2 - W = L (1)
And the area is
A = L * W sub (1) for L
A = (P/2 - W) * W simplify
(P/2) W - W^2 rearrange
-1W^2 + (P/2)W
a = -1 b = (P/2)
Again....the "W" that maximizes the area is given by -b / [ 2a] =
- ( P/2) / [2 ( -1) ] = - P/ -4 = P /4
And when W = P/4 L = P/2 - P/4 = P/4
So..... W = L = P/4 = 100 / 4 = 25 ft
This will always be true, AT......for any perimeter......area is maximized when W = L = P/4
