5) Since BAD is trisected, angle SAD = 30°
And triangle SAD is a 30 - 60 - 90 triangle
So.......AD = √3SD = √3 * 1 = √3
And angle TAD = 60° so triangle ATD is also a 30 - 60 - 90 triangle
And TD = √3 AD = √3 √3 = 3
So CD = CT + TD = 2√3 - 3 + 3 = 2√3
So......the area of ABCD = CD * AD = 2√3 * √3 = 6 units^2
