x= -3, -2, -1, 0, 1, 2, 3,
f(x)=63, 8, -1, 0, -1, 8, 63
Notice that when the graph progresses from (- 2, 8) to (-1, -1)...it passes through the x axis for the first time....so this is one zero
And then (-1, -1) to (0,0) ......given the fact that we're not told that graph reaches a posiitive value before it progresses to (1, -1)....we have to assume that it only "touches" the origin....this means that, -- at a minimum- two more "zeroes" are added
And from (-1, -1) to (2,8) it passes through the x axis once more....and a last zero is added
So...at a minimum, the graph has a degree of 4 [ the fact that the graph just "kissses" the origin means that the actual degree could also be 6, 8, 10, etc. When a graph just touches the x axis, it means that 2n zeroes are added.......
Your second one is correct !!!
