f(g(x) = [2x^2 + 3 ] - 1
g (f(x)) = 2 [ x - 1 ] ^2 + 3
So.....we are trying to solve
f(g(x) = g(f(x))
[ 2x^2 + 3 ] - 1 = 2 [ x - 1 ]^2 + 3 simplify
2x^2 + 2 = 2 ( x^2 - 2x + 1) + 3
2x^2 + 2 = 2 x^2 - 4x + 2 + 3 subtract 2x^2 from both sides
2 = -4x + 5 add 4x to both sides, subtract 2 from each side
4x = 3 divide both sides by 4
x = 3 / 4
