f(x)=2x^2−5x−3 and g(x)=2x^2+x
(f * g) (x) =
2x^2(2x^2 + x) - 5x(2x^2 + x) -3(2x^2 + x)
4x^2 + 2x^3 - 5x^3 - 5x^2 - 6x^2 - 3x
-3x^3 - 7x^2 - 3x
(p * c) =
(120 -2x) (50 + 5x)
So
(p * c) (2) =
(120 - 2*2) (50 + 5*2) =
(116) (60) =
$6960
The last option is correct
f(x)=3x^2+4x and g(x)=2x^2−x+1
(f + g)x =
[ 3x^2+4x ] + [ 2x^2−x+1 ] =
5x^2 + 3x + 1
If f (2) = 5
Then this implies that :
f-1 (5) = 2 ...so....
2f-1 (5) + 1 = f-1 (5 + 4)
2*2 + 1 = f-1 ( 5 + 4)
5 = f-1 (9)
2f-1(9) + 1 = f-1(9 + 4)
2*5 + 1 = f-1(13)
11 = f-1 (13)
2 f-1 (13) + 1 = f-1(13 + 4)
2 * 11 + 1 = f-1 (17)
23 = f-1(17)
8t^2 ≤ 3 - 10t rearrange as
8t^2 + 10t - 3 ≤ 0 factor
This graph may help :
https://www.desmos.com/calculator/tmxfctalnk
The values that make this true are t = [ -1.5, 0.25 ]
It must be 1
That's pretty short ....!!!
Volume of a cone =
3.14 * (diameter/2)^2 * height
________________________ =
3
3.14 * ( 3/2)^2 * (6)
________________ =
3.14 * 2 * (9/4) ≈ 14.13 in^3
B
A
XZ / YZ = DF / EF
15 / 10 = DF / 8
3 / 2 = DF / 8 multiply both sides by 8
8 * 3 / 2 = DF
24 /2 = DF
12 = DF
3 + 8 + 13 + 18
The 19th term is given by
3 + 5(19-1) = 3 + 5(18) = 93
And the sum is given by
[ 93 + 3] (19/2) =
96/2 * 19 =
48 * 19 =
912
The second isn't showing up for me
For the third, we have
(n) (n + 1) where n = 75
75 * 76 =
5700
