CPhill

OK....!!!

Note that since AB  = AC....then angles ABC  and ACB  are  equal.....

So ACB  =  (180 - 24) / 2  =   156 / 2  =  78°

And ACD  is supplemental to ACB...so ACD  = 180 - 78  =  102°

And since AC  = CD....then angles ADC  and CAD are equal

So.... ADC  =  (180 - 102) / 2  =  78/2   =  39°  =  "x"

Can you just upload the image  ???

No image is shown, sageatron.....  

The minimum value  is :     -6

The area  is  just

(1/2)  * (product of the legs) =

  (1/2) (14 * 14)  =   196/2  =   98 units^2

f(x)  =  cos (x)

Reflecting it over the x axis  produces

f(x)  =  -cos(x)

Shifting it two units down  produces 

f(x)  =  -cos(x)  - 2   =  g(x)

5w - 3  = 3w + 15       add 3 to both sides

5x = 3w + 18      subtract 3w from both sides

2w  = 18       divide both sides by 2

w  = 9

In the form

Acos(Bx) + C ...the amplitude  =  A

So....the amplitude  is   3

The legs of the triangle  will have a length =   hypotenuse / √2  =  14√2 / √2  =  14

f(x)  =  3cos(x) -  2.5

The  max  value for this graph  is    y  = (3 - 2.5)   =  .5

The min value for this graph  is  y =  (-3 - 2.5) = -5.5

So....the midline is given by :

y  =   [ .5  + - 5.5 ] / 2   =  -5/2  =  - 2.5

See the graph here :  https://www.desmos.com/calculator/gnggynixpz