CPhill

Third one

Another triangular prism

The top/bottom  are  triangles with a base of 15m  and a height  of 11.2 m

So...the area of the top/bottom  is  15 * 11.2  = 168 m^2

The sides are rectangles  each with a height of 7m  and  widths of  [ 13, 14 and 15 ] m

So...the total area of the sides  =  7 [ 13 + 14 + 15  ] = 294 m^2

So...the total surface area  is   168 + 294   =  462 m^2

Second one

This is a hexagonal prism

The top and bottom are hexagons...comprised of 6 congruent triangles...each with a base  of 11  ft and a height of 9.5 ft

So...the area of the top/bottom  =  6 (1/2)(11)(9.5)  =  313.5 ft^2

The sides are 6 congruent rectangles   each with a height of  6ft and a width of 11 ft...so the area of the sides is

6 * (11) ( 6)  =396 ft^2

So...the total surface area  =   [313.5 + 396 ] ft^2   =  709.5 ft^2 

First one

We have two triangles comprising the top/bottom  each with a base of 17 cm and a height of 4.9 cm

The area of these  =  17 (4.9)  = 68.6 cm^2

The sides are three rectangles...each with a height of  9cm  and  widths of  [ 7 , 13 and 17 cms]

The total area of these  is  [ 9 ] * [ 7 + 13 + 17  ] =  9 [ 37]  =  333 cm^2

So...the total surface area of the first  figure [ a triangular prism ]  is  [ 68.6 + 333 ] cm^2  =  401.6 cm^2

3√-50  =

3√  [ -1  *  25  * 2 ]  =

(3 *i * 5 )√ 2  =

15i√2

1.)   (4x^3 y^2) ^3/10  =

¹⁰ √  ( [ 4x^3 y^2 ]^3 )  =

¹⁰ √ [64 x^9 y^6 ]

HAHAHA!!!....we didn't really do anything  !!!!

In the sample problem...I think 

p  = If you go to school

q  = You must make a right turn

r  = You must use a turn signal

So

Law  of Detachment  says

p → q    and  q  → r    [ both are true ]

Law of  Syllogism says [ since both of these are true ]

p →  r

See if this helps, Owen  :

https://www.shmoop.com/logic-proof/detachment-syllogism.html

Nope...no better answer......good job  !!!

Shoes  = 9%

Socks = 52%

Add them together   =  61%