27 * 9^(3x) =
3^3 * (3^2)^(3x) =
3^3 * 3^(6x) =
3^ (3 + 6x)
So...k = 3 + 6x
Multiples of 5 = 5 and 10
Ways to roll a 5 = (1,4) ( 4,1) (2,3) (3,2)
Ways to roll a 10 = (5,5) (4,6) (6,4)
We have 7 possible outcomes for a multiple of 5...and there are 36 possible outcomes in total
So P (multiple of 5) = 7 / 36
Don't know much about this, NSS...but...apparently the "formula" for calculating APY is :
APY = ( 1 + r/n)^n -1
Where, in our case....r = 12% = .12 and n = 12
So
APY = (1 + .12 / 12)^12 - 1 ≈ .1268 ≈ 12.68%
In the formula
P = 3500
r = .027
n = 1 [interest is compounded once a year ]
t = 3
So we have
A = 3500 ( 1 + .027/ 1 )^(1*3) = $3791.22 ⇒ "B"
I = Prt
I = 6000 * (.07) * (4) = $1680 ⇒ "B"
C = good
I believe that "3" is the answer
The mode is/are the value(s) that occur the most number of times
"7" appears 3 times....does another value appear a greater number of times ???
Which one is this, NSS ???
Order the data from low to high
Subtract the lowest value from the highest.....this will be the range, NSS
6 6 7 7 7 9 10 10 10 10 11 12
We have an even number of values
The median is found by adding the 6th and 7th values and dividing this sum by 2
Can you find the median based on this, NSS ??
