a. sin^2x = 2sin^2(x / 2)
Note sin^2 (x / 2 ) = 1 - cos x
So we have
sin^2x = 1 - cos x
1 - cos^2x = 1 - cos x subtract 1 from both sides
-cos^2x = -cos x multiply through by -1
cos^2x = cosx
cos^2x - cos x = 0
cosx ( cos x - 1) = 0
Set each factor to 0 and we have that
cos x = 0 and this happens at pi/2 + n*pi where n is an integer
and
cos x - 1 = 0
cos x = 1 and this happens at 0 + n* 2pi where n is an integer