CPhill

y = (-7/3) + 2

The y intercept  is at  2   ⇒   (0 , 2)

The slope of the line  is  -7 / 3

Go down 7 units from (0, 2)   =  (0, 2 - 7)  =  (0, -5)  

Go to the right by  3  units from this point  =   [ 0 + 3, -5)  =  (3, -5)

Plot the two coordinates in red   and draw a line through them....this is the graph

It should look like this   : https://www.desmos.com/calculator/ejl49oydio

Mmmm.....I''m not sure  what "RHS" means,  either...but...here's a proof

BD  = CA   [ diameters of a circle are equal ]

Central Angle BOA  = Central Angle COD  [ vertcal  angles are equal ]

Chord BA  =  Chord CD  [ equal central angles span  equal chords  ]

AD = AD    [ reflexive property ]

So  BD = CA, BA = CD  and AD =AD

So...by S-S-S   triangle ABD  is congruent to  triangle DCA

We need to know three other things to answer this

1 - Area of  US  in square miles

2 - CA's  population

3 - CA's  area in square miles

The  standard deviation  = sqrt (variance)  = sqrt (4)  = 2

Triangle  BDC  is similar to triangle BEA

Therefore     EA :  DC  = 20 : 10   = 2 : 1

Therefore...there are 3 parts to the total  height of the figure

And...since the triangles are similar..it means that the height of triangle BEA  to the height of triangle BDC = 2 : 1

So....the height of  triangle  BEA  = h  =  (2/3) (36)   = 24 cm

The variance is the square of the standard deviation  = 4^2   = 16

Upper exterme  = max value of data set  =  10

Five values

Minimum value = 46

Max value = 66

Median of the data set = 58  [ the red line ]  = Q₂ = Second Quartile

First quartile  = 55 = Q₁    [it's the median of the data  set points to the left of Q₂ ]

Third quartile = 63  = Q₃  [ it's the median of the data set points to the right of Q₂ ]

Example

Let   triangle ABC  have the following coordinates  ...A  = (0,0)  B  = (0, 3)  and C  = (4,0)

Let triangle DEF   have the following  coordinates ... D = (5,0)  E = (1,3)  F (1,0)

First calculate the distances between AB, AC  and BC

AB  =  sqrt  [ (0 - 0)^2 + (3 -0)^2 ] = sqrt [9] = 3

AC = sqrt [ (4 - 0)^2 + (0 -0)^2  ]  = sqrt [ 16]  = 4

BC = sqrt  [ (4 - 0)^2 + ( 3-0)^2 ]  = sqrt [ 16 +  9 ] = sqrt [25 ] = 5

Next calculate the distances between DE, DF and EF

DE  = sqrt [ (5 -1)^2 + (3 - 0)^2 ]  = sqrt [ 4^2 + 3^2 ] = sqrt [ 16 + 9 ] = sqrt [25]  = 5

DF  = sqrt [ (5 - 1)^2  + ( 0 - 0)^2 ]= sqrt [ 4^2] = sqrt [ 16] =4

EF  = sqrt [ (1 - 1)^2 + (3 - 0)^2 ] = sqrt [ 3^2]  = sqrt [9] = 3

Since AB = EF  and AC = DF  and BC = DE

Then..by S-S-S   these triangles are congruent

I'll let you see if these are congruent...remember....the distances must "match" to have S-S-S  congruecy

triangle ABC  .... A  = (0,0)   B  = (0, 4)  C  = (3,0)

triangle DEF  ...D  = ( 1,0)    E  = (4, 0)   F  = (0, 5) 

"Oualitative" data doesn't use  "hard"  data.....it might measure "subjective" data such as  appearance, taste, etc.

So.... "B"  is qualitative  [ your tires may appear "good" to you but may appear "not good" to someone else ]