CPhill

Mmmmm...none of these...

A  roots are -6  -3, -2  -1

B roots are  -3, -1, 2, 6

C is the same graph as  B

D roots are  1,   2,   3,   6

OOPS...thanks, guest for the correction  !!!

Nice job, tertre  !!!

I think it should have read..." during a hot Summer week..."

Graph C

It crosses the x axis at  -2, 0 and 3   [ its roots ]

Triangles ADE, CD share the same base  (AC)

And triangles ADE and CDE  have the same altitudes...so....their bases are to each other as their areas

So  AD /DC  = 9/6   = 3/2

So...there are  5 equal parts of AC....and  AD  is 3 of them

So......AC / AD  =  5/3

Since triangles ADE and ABC are similar....the scale factor  of triangle  ABC to  triangle  ADE  is  (5/3)

So...  [ABC ] =  [scale factor of  ABC to ADE]^2  *  [ ADE ]  =

(5/3)^2 *  [ 9 ]  = 

25 / 9   *  [9]  =

25 units^2

FC  = 12 - 5  = 7

triangle EFC  similar to triangle BDE

So we have that

EF / FC  = BD / DE

5 / 7  = BD / 5

BD =  25 /7   [ the same as guest's answer ]

Area of  3 slices  of 12 in diameter  =  6 in radius pizza  =

(3/8) pi (6)^2    (1)

Area  of 3 slices of 16 in = 8 in radius pizza  =

(3/8) pi (8)^2     (2)

(2)  - (1)  =

(3/8) pi  [ 8^2 - 6^2 ] =

(3/8) pi [ 64 - 36 ] =

(3/8) pi [ 28]  =

(3 * 28 ) / 8  pi  =

[ 3 * 7 ) / 2  pi  =

(21/2) pi   in^2

Your answer is the same  !!!!

The scale factor for the  top shaded triangle  is  1/4  of ABC

So..its  area  is  scale factor ^2  *  [ ABC]   =  (1/4)^2 * [ABC ]  =  [ ABC ] /16

For the top 1/2 of the figure....the scale factor  is 1/2  of ABC

So...its  area  =   (1/2)^2 [ ABC ]  =  [ ABC ]  / 4    =  (1)

For the top 3/4 of the figure....the scale factor is 3/4 of ABC

So ...its area  =  (3/4)^2 [ ABC ]  = [ABC] *(9/16)  =   (2)

So....the bottom shaded area  = (2) - (1)  =  [9/16 - 1/4] [ABC ] =

[5/16] [ ABC] 

So....the total of the shaded ares  =   [ ABC ] / 16  +  [5/16] [ABC ] =  

[ 6/16] [ ABC ]  =

[3/8] [ ABC]

Here's what I get, NSS

For a new car

P = 350

r = .0279/12

n = 72

A =  350 [ (1 + .0279/12)^72 - 1 ] / [(.0279/12) ( 1 + .0279/12)^72 ] ≈ $ 23,178.95

For a used car only  r is different....it is   (.0329/12)

So we have

 350 [ (1 + .0329/12)^72 - 1 ] / [(.0329/12) ( 1 + .0329/12)^72 ] ≈  $ 22,840.34