Second one
Because DC is parallel o AB, then triangle BAF is similar to triangle EDF
And since the side of the square = sqrt (36) = 6
Then DE + EC = 6
DE + 2DE = 6
3DE = 6
DE = 2
So
[AB ] / [AD + DF ] = DE / DF
6 / [ 6 + DF ] = 2 / [ DF ] cross-multiply
6 [ DF ] = 2 [ 6 + DF ]
6DF = 12 + 2DF subtract 2DF from both sides
4DF = 12 divide both sides by 4
DF = 3 = height of triangle DEF
So area of DEF = (1/2)DE * DF = (1/2) * 2 * 3 = 3 units^2
