OK....but be careful with this method..it isn't foolproof in all cases
For instance
y = 3x and y = (1/4)x
Putting 0 into the first returns 0
So (0,0) is on the first graph
So....putting the "returned" value of 0 into the second graph gives us back the original value of 0
So...these would appear to be inverses....but they are not
Using the foolproof method
3 [ (1/4)x ] = (3/4) x
This isn't "x"......so....we can stop here....they are NOT inverses !!!
