Thanks, Fiora and Sincerelyrose....
 
Here is the proof :
 

 
 
Since  BD   = AB...then angles ADB  and DAB  are equal
And angle AEB  = 90
And since the diagonals bisect each other...then AE  = BE
So...angles DBA  and CAB  are equal  = 45
 
Then...in triangle DAB....angle DBA  =  45
Andl angles DAB  and ADB  are equal....so
DAB  =  [180 - mDBA] / 2  =   [ 180 - 45 ] /  2 =   135 / 2  = 67.5
 
And...using the same sort of argument, we can show that angle  CBA  also  =  67.5
 
And.....these are the  two acute angles of the trapezoid....so their sum  = 135
 
 
 
  
 