-32 (2) ^(x - 3) + 3
Let x = 0
-32 (2)^(0 - 3) + 3
-32 (2)^(-3) + 3
-32 / (2)^3 + 3
-32 / 8 + 3
-4 + 3 =
-1 = y intercept
Very nice, Melody !!!
The functions are inverses of each other
The graphs of the functions are symmetric over the line y = x
Both are correct......good job !!!!!
Here's the second one :
x^2 + 3x - 28
____________ factor top/bottom
x^2 -7x + 12
( x + 7) ( x - 4)
____________ "cancel" the ( x - 4) factor on top/bottom
(x - 3) (x - 4)
( x + 7)
_______ ( with x not equal to 4)
( x - 3)
First one
Let x = -4
So (-4)^2 = 16
So....x^2 > 9
Second one
Let n = 41
So
41^2 + 41 + 41 = 41 ( 41 + 1 + 1) = 43 *41 so...it is not prime
Last one
In "three-space," we can have two lines that never meet but are not parallel....these are known as "skew" lines
What Melody, EP and DC said.....!!!!
I'm far from an "expert," but I try to help where I can.....
HAHAHA!!!!.....maybe you're better than you think you are....!!!!
First one....correct !!!
Second one ....I think "B" is what they want...however.....your answer could "factor" as [ ( x + 5) - 1 ] [ ( x + 5) + 1 ] = 0...so....it's a legitimate step, too....!!!
Third one...you're close...but it's "A"...note
(t - 3) ( t - 5) = 0
t^2 - 3t - 5t + 15 = 0
t^2 - 8t + 15 = 0
Last one....correct !!!
OK....!!!
