The side of the smaller square is 1 cm
The side of the larger square is 4 cm
Draw segment BC parallel to the bottom side of the figure
So....the distance from B to C = 1 + 4 = 5
And the distance from C to A = 4 - 1 = 3
So....using the Pythagorean Theorem, we have
AB = sqrt ( BC^2 + AC^2 ] = sqrt [ 5^2 + 3^2 ] = sqrt [ 34 ] =
5.8 units
