CPhill

9x - 45  ...... just "take out" a "-1" and reverse the order of terms

So we have

-1 (45 - 9x)

OK...here's No. 3

y ≥ -2x² -2x + 1

There's not much to  "solve" by hand, here.....a graph of the solution area is more appropriate

Note that the solution area (in blue) lies "above" and just "touching" the parabola (this is indicated by the "≥" symbol)

I don't know if this is what you're looking for, or not.......

Nice one, Melody.....!!!

Just put this into the onsite calculator.....!!!

I don't see any problems on here, Phanolo......!!!!

Can you message me with your problem(s) ???

A polynomial always has a domain of all real numbers.....

I'm not seeing anything here.......

2−(4-7*(8-2^2)+9)+[−6+(−3+8)] =

2 - (4-7*(8 - 4) + 9) + [-6+(5)] =

2 - (4-7*(4) + 9) + [-1 ]  =

2 - (4 - 28 + 9) + [-1] =

2 - (-24 + 9) + [-1] =

2 - (-15) - 1  =

2 + 15 - 1 =

17 - 1 =

16

[1 + (5/(100 – 5))] ^ [365/(55-10)] – 1   simplify

[1 + 5/95] ^{[(365/45) - 1]}  =

[1 + 1/19] ^(64/9) =

[20/19] ^(64/9) =  (about 1.44)

Take both things out of the absolute value bars and solve two equations

2v + 3  = 2v + 6         and        -(2v + 3) = 2v + 6

The first equation has no real solutions

For the second, we have

-2v - 3  = 2v + 6           subtract 2v from both sides and add 3 to both sides

-4v = 9                         divide both sides by -4

v  = -9/4   = -2.25