3. Three of the four vertices of a rectangle are (5,11), (16,11) and (16,-2). What is the area of the intersection of this rectangular region and the region inside the graph of the equation (x-5)^2+(y+2)^2=9? Express your answer as a common fraction in terms of pi.
The remaiining vertex of the rectangle is (5, -2)
And this is the center of the circle, as well
Here's a graph :

The region is just the area of a quarter-circle with a radius of 3 =
pi * (3)^2 / 4 =
9/4 pi units^2
Thanks to PM for spotting my earlier mistake......!!!
