CPhill

Welcome back, rarinstraw.....!!!

1.

6.12 m

There are 3.28 ft to 1 meter....so

(6.12) (3.28)  ≈  20.07 ft

There are  1.094   yards to 1 meter

So

(6.12) (1.094) ≈   6.7  yards

2.     3.21 / 4   = .8025 hrs = .8025 (60)  = 48.15 min

See the answer here :  

https://www.wolframalpha.com/input/?i=square+root+(%5B+(1.8167)%5E2+%2B+(0.8167)%5E2+%2B+(3.1167)%5E2+%2B+(-3.2833)%5E2+%2B+(-1.1833)%5E2+%2B+(-1.2833)%5E2+%5D++%2F++5)

 g(x)=2√x+3

The transformed function vertically stretches the parent by a factor of 2  and up 3 units 

The domain is  [ 0, inf )

The range is [3, infinity )

if the transformed funtion is supposed to be

 g(x)=2√ (x+3)

The parent is vertically stretched by a factor of 2  and shifted to the left by 3 units

The domain is [ -3, infinity )

The range is [0, infinity )

a + b =  8

b + c  = -3

a + c = -5

Subtract the second equation from the first  and we have that

 a - c =  11      add this to the third equation  and we get that

2a = 6

a = 3

a + b = 8

3 + b = 8

b = 5

a + c = -5

3  + c = -5

c =  - 8

So   abc  = (3) (5)(-8)   =  - 120

What  is G    ????

It's not defined in the problem....

Box 1   ⇒   P(B|A)

Box 2 ⇒  Does not affect

Box 3 ⇒  P(B|A) = P(B)

Note that since we want the answer in minutes....2/5 hr  = (2/5)(60) =  24 min

We have this system

B + C + D  =  3A

A + C + D = 4B

A + B + D  = 2C

8A + 10B + 6C = 24    ⇒ 4A + 5B + 3C = 12 

This system isn't hard to  solve, but it's a little tedious

Using WolframAlpha, the solutions  (in minutes)  are

A = 1

B = 4/5

C = 4/3

D = 13/15

So  13 + 15   =    28

P.S. -  I can show  you how to solve the system by hand....if you want.....

3(x - 2y) - 4(2x + 3y)

    for x = -1 and y = 3

3 [  -1 - 2(3)  ]  -  4 [ 2(-1) + 3(3) ]   =

3 [  - 1 - 6 ]   - 4 [ -2 + 9 ]   =

3 [ - 7 ]  - 4 [ 7 ]  =

-21  - 28    =

-49

Thanks, guest.....!!!!