CPhill

Shreveport, LA

63°    with a high of 67°

Come see me in six months......that's when it's miserable

From the top left to the right

1. None of these  (angles 1, 2  are supplemental pairs)

2. Corresponding angles

3. Corresponding angles

4. Alternate exterior

5. None of these

Thanks, heureka.....I thought there might be a cyclic pattern to this.....!!!!

First one

Here's a possibility :

(-7a^6) (12b^10)

Second one

The new side length = 2 * 2x^5 =  4x^5

The new volume  = (side)^3 =   (4x^5)^3  =  64x^15

z is supplemental to the  43° angle 

So....the sum of their measures = 180°

Therefore

z + 43 =  180            subtract 43 from both sides

z = 137°

These are vertical angles....so....they are equal....thus

3x + 50 = 6x - 10     add 10 to both sides, subtract 3x from both sides

60 = 3x           divide both sides by 3

20 = x

This is true.....

Thanks, EP.....!!!!

x= { -1, 1, 2 } and y = { -2, -1, 0, 1, 2 }

The positive ones are

(-1)^(-2)    =   1         (1)^(-2) = 1           (2)^(-2) = 1/4

(-1)^0     =  1             (1)^(-1) = 1           (2)^(-1) = 1/2

(-1)^2     =1               (1)^(0) = 1            (2)^(0) =  1

                                 (1)^(1) = 1             (2)^(1) = 2

                                 (1)^(2) = 1             (2)^(2) = 4

There are  5  distinct values

y = 24 / [ x + 3 ]

y [ x + 3 ] = 24

yx + 3y = 24

yx = 24 - 3y

x =   [ 24 -  3y ] /y       "swap" x and y

y =  [ 24 - 3x ] / x  = f^-1(x)

So 

 g(x) =  3f^-1(x) =    [ 72 - 9x] / x

So

g (x) = [72 -  9x ] / x = 15

72 - 9x = 15x

72 = 24x

x = 72/24   =  3