a. N = 10000 ( 2)^(t/40) where N is the number of bacteria after t minutes
b. N = 10000 (2)^(60/40) ≈ 28284
c. 5000 + 8 = 10000 (2)^(t/40)
50008 = 10000 (2) ^(t/40)
50008 /10000 = 2^(t/40) take the log of each side
log (50008 / 10000) = log 2^(t/40) and we can write
log (50008 / 10000) = (t/40) log (2)
t = 40 log ( 50008 / 10000) / log (2) ≈ 92.9 minutes
d. Here's the graph ( subbing y for N and x for t)
https://www.desmos.com/calculator/t5egnmgcks
