We can choose any 4 of the 9 people to be on 1 of the 3 teams
And then we can choose any 4 of the 5 remaining people to be on 1 of the remaining 2 teams
The last person is on the last team by default
So
C ( 9,4) * C ( 3,1) * C(5,4) * C (2,1) = 3780 ways
Not totally confident about this, but BuiderBoy will probably have the correct answer !!!! (LOL !!! )
