2.   H is the  orthocenter of the triangle  Draw CH  and extend it  to F where CF is the third altitude of the  triangle
  
 Angle AHE  =  180   - 128 =  52
 Angle AEH  = 90
 Angle HAE  =  90  - 52 = 38
  
 Angle BAH  =  28
  
 Angle BAC =  Angle BAH + Angle HAE  =  28 + 38  = 66 
  
 Angle CFA =  90
 Angle BAC =  66
 Angle FCA =  180 - 90 - 66   = 24
  
 But Angle FCA = Angle HCA =  24
  
  
  
 