2. H is the orthocenter of the triangle Draw CH and extend it to F where CF is the third altitude of the triangle
Angle AHE = 180 - 128 = 52
Angle AEH = 90
Angle HAE = 90 - 52 = 38
Angle BAH = 28
Angle BAC = Angle BAH + Angle HAE = 28 + 38 = 66
Angle CFA = 90
Angle BAC = 66
Angle FCA = 180 - 90 - 66 = 24
But Angle FCA = Angle HCA = 24