CPhill

"c" is easy.... it's = 7

The vertex is at (h, k) = (-1, 8)   and the point    (2. -1) is on the graph

So we have

y = a(x - h)^2 + k

-1 =a(2- (-1))^2 + 8

-1 = a(3)^2 + 8      subtract 8 from both sides

-9 = a(9)     divide both sides by 9

-1 = a  

And the x coordinate of the vertex is given by  -b/2a

So we have 

-1 = -b/2(-1)  →  -1 = -b/-2 →  b = - 2

So.....our function is

y = -1x^2 - 2x + 7

So

a + b + 2c =

-1 + (-2) + 2(7) =

11

-2(y-4)=20-2y-12     simplify

-2y + 8 = 8 - 2y

8 - 2y = 8 - 2y

Since both sides are the same, there are infinite solutions to this......!!!!

There are four triangles each having an area = bh/2 = (10*13)/(2) in²

So......(4)(10*13)/2 in²   = 260 in²

And the area of the base = 10²   = 100in²

So...the total surface area =  [ 260 + 100]in² = 360 in²

Here it is.....

0.000000000000000000000000008756510762696520338488732800739166037

Jerry has a box contained red, blue, and green markers. The ratio of red markers to blue markers is 5:2. The ratio of blue to green markers is 3:5. What is the ratio of red markers to green markers?

Note, that for every 7 red and blue markers, 2  are blue and 5 are red

So, for every  6 blue markers, 15 are red

And for every 8 blue and green markers,  3 are blue and 5 are green

So, for every 6 blue markers, 10 are green.

So, the ratio of red markers to green is 15 : 10    or just 3 : 2

Here's another way to see this without doing much math.

If the perimeter is 42, each side is 14.  And this is 2 more than 3 times the original length.

So, subtracting 2 from a side = 12.

And this is 3 times the original length.......so the original length was 4.

-(2 + 2/11)  / -(2 + 1/2)   =

(-24/11)  /  (-5/2) =

(24/11) x (2/5) =

48 / 55

Give us the sides and any angles you might have.....

h7.....I think the question might be this...

1.3 x 10⁵   = 130, 000

So.....the two things are equal

I worked out the "long method"....here it is

               x ^ 4   -  x^3y   +  x^2y^2  -  xy^3   + y^4

            -----------------------------------------------------

x + y     [  x^5                                                          +y^5 ]

                x^5    + x^4y

                          - x^4y 

                          - x^4y   - x^3y^2

                                       + x^3y^2

                                          x^3y^2    + x^2y^3

                                                         -x^2y^3

                                                         -x^2y^3 - xy^4

                                                                       +xy^4

                                                                        +xy^4  + y^5

                                                                       -------------------

                                                                                          0