CPhill

We would have to know something else (like the length of the hypoteneuse, for instance) to find the sides.

Just add all the sides......

4x-1 intercepts the line 2x+5

And I assume you want to find the intersection point???

Let's just set these two equations equal...so we have

4x - 1 = 2x + 5     subtract 2x from both sides and add 1 to both sides

2x = 6                  divide each side by 2

x = 3

And to find y, just plug this value into either equation...I'l use the first

4(3) - 1 = 11

So the soution is (3, 11)

I believe you want to find the angles at the corners....OK....

By definition, a square is a rectangle....and by extension....a rectangle is a parallelogram with four right angles.....so...the angles at the corners of a square are all right angles = 90°

This is solved just like this one.....

We'd need to see the graph to answer this question......

This is solved just like this one.....

NO !!!!!!!!!

The tangent of an angle returns the value for that angle [where the tangent is defined ]

Tan^-1  is the arctangent (also called the tangent inverse)....and  this returns the angle back to us

Here's an example

tan(60°) = √3

But

tan^-1 (√3 ) = 60°

See the difference ??

We cannot take the log of a negative number or 0

Notice that any value in (-∞, -1) is OK

Notice that values in [-1, 1] either give us something that is negative or undefined

And note that any value in (1, ∞) is OK

So, the domain is just (-∞, -1) U (1, ∞)

Here's a graph that will help you see this...

This just says that the understood base, (10), raised to the thing on the other side of the equal sign, (x) = 100   ....   like this....

10^x = 100

BTW   .....  x = 2