CPhill

According to this site ....  about $160....

OK....post it...we'll see what we can do....!!!

2lgx=12   divide both sides by 2

lgx = 6     which means that 10^6 = x = 1,000,000    (assuming that  'lg" is base 10)

We have A = Pe^(rt)   where r = .11 and t = 2  and P is the invested amount

8000e^(.11*2) = $9968.61   after two years

770 x 5.9 x 10^12 = 4,543,000,000,000,000     ...  in words....about 4.5 quadriliion miles

4z/9-2=-8     add 2 to both sides

4z/9  = -6     multiply both sides by 9

4z = -54       divide both sides by 4

z= -54/4  = -27/2

d/dx ( sin^4/4 - sin^6/6 + C) =

sin^3x(cosx) - sin^5x(cosx) =

cosx(sin^3x)(1 - sin^2x) =

cosx (sin^3x)(cos^2x) =

sin^3xcos^3x

And           

d/dx(-cos^4x/4 + cos^6x/6 + C)=

-(sinx)(-cos^3x)   - (sinx)cos^5x  =

(sinx)(cos^3x)(1 - cos^2x) =

(sinx)(cos^3x)(sin^2x) =

(cos^3x)(sin^3x)  = sin^3xcos^3x

And they are exactly the same.....!!!

Let the number of text messages = n   ..so we have

20 + .10n = 30 + .05n    subtract 20, .05n from both sides

.05n = 10    divide both sides by .05

n = 200 text messages will make the cost of the plans equal

The lateral surface area (area of the sides) is given by 4*6*5  = 120 sq m

And the total surface area adds the area of the tp and bottom = 2*5^2 = 50 sq m

So the ratio of the lateral surface area to the total surface area = 120/(120 + 50) = 120/170 = 12/17

By "lateral area," I assume you mean the area of the sides.....but we can't answer this one because it depends upon how the rectangular solid is oriented as to what the "sides" are....