CPhill

R = [ mB - T ] / K   multiply both sides by K

KR  = mB - T      add T to both sides

KR + T  = mB   divide both sides by m

[KR + T ] / m = B 

No prob, dude  !!!!

Let me add one thing to what Melody said.....

Combinations count sets

Permutations count orderings within the sets

Thus, with sets of more than one element.....the number of permutations will be larger than the number of combinations....!!!

Anonymous.....the store would go broke if they sold it for less than they bought it...!!!!!

$3.90 (1.30)  = $ 5.07 

A bearing of 220 degrees sets up a triangle with an apex angle of 40 degrees and an opposite side of 80km.....and we're trying to find the hypotenuse....so we have

sin40 = 80/ d      where d is the distance we want

Rearrange as

d  = 80 / sin 40 =   about 124.5 km 

Hit the "2nd" bitton on the calculator......you will see the "atan" button.....this is the same as the tangent inverse....

Use the tangent inverse....we have

atan(rise  /  base )   = the angle in degrees

 R= mB - T / K    add  T/K  to both sides

R + T/K   = mB    divide by m on both sides

[ R + T/K ] / m   = B

And there you go....!!!!

The sum of any three angles of a triangle can only be 180°......your triangle can't exist in Euclidian geometry....

There are infinite solutions to this......here's one.....

-30 +( -10 ) + ( - 2 ) +  20

The biggest and smallest have a difference of 50 ....  and the sum = -40 + 18 = -22

{I'm not sure this interpretation is correct......you may have meant something else ??? }