Simplify:
f(x) = x^2 + 4x + 2 = (x + 2)^2 - 2
So, the top graph is the correct graph.
f(x) = g(x) when the graphs intersect. The intersection point is (0, 2), or x = 0
The graph is skewed to the right since most of the numbers are given at the left side (0 to 3). So, the answer is A.
11 divided by n^3 ==> \(\frac{11}{n^3}\)
Area = (big rectangle) - 2(small rectangle)
= (10)(7) - 2(3)(5)
= 70 - 30
= 40 cm^2
\(\frac{1}{2} \sqrt 5 + \frac{ (\frac{9}{2} \sqrt5)}{2}\)
\(\frac{\sqrt{5}}{2} + \frac{9\sqrt{5}}{4} = \boxed{\frac{11\sqrt{5}}{4}}\)
Volume of roll = (volume of big cylinder) - (volume of little cylinder)
The volume of a cylinder with radius r and height h is \(\pi r^2 h.\)
\(V = \pi (\frac{12}{2})^2(26) - \pi (\frac{4.2}{2})^2(26) = \boxed{821.34}\) cm^3.
Suppose this is interest compounded continuously.
P = principal (initial) amount = 6970400
R = annual rate = 0.8%
n = compound (continuous) ==> n = e = 2.718
t = time = 1 year
Pe^(rt) = 7,026,386.85
Multiply all the ratios together:
\((\frac{a}{b})(\frac{b}{c})(\frac{c}{d}) = \frac{a}{d}\)
Hope this gets you started.
The coordinates ABCD form a rectangle with sides AB (4) and AD (7).
The area is 4 * 7 = 28 and the perimeter is 2(4 + 7) = 22.
There are a total of 6 racers that medals could be awarded to.
There are 6 choices to pick a gold medalist, 5 choices for a silver medalist, and 4 choices for a bronze medalist. So, there are 120 ways.
