Let the entire thing be equal to x. Then,
\(\sqrt{3 + x} = x\)
\(3 + x = x^2\)
Use the quadratic formula to solve for x.
This question has been answered already: https://web2.0calc.com/questions/help_75583
Let minor arc SF be x degrees.
1/2(210 + x) = 130
210 + x = 260
x = 50 degrees
(For similar theorems about angles in circles, this might be helpful: https://www.onlinemathlearning.com/central-angle.html)
f(-2x) ==> reflect across y-axis, horizontal compression of factor 2
f(-2x) has domain [-4, 2].
(please correct me if i'm wrong)
There is another way.
Area = 1/2 * (base) * (height)
= 1/2 * 9 * sqrt(5^2 - 3^2)
= 18
478 * 9 = 4302
+ 478 * 30 = 14340
-------------------------------------
478 * 39 = 18642
I will do part A) as an example.
general form: f(x) = Asin(x - phi) + y
A = amplitude
phi = horizontal shift
y = vertical shift
A) amplitude = | -2 | = 2
period = 2pi/x = 2pi
We can complete the square.
\(x^2 + 4x + 3 = (x^2 + 4x + 4) - 1\)
\(\boxed{(x+2)^2 - 1}\)
40 deg = 2pi/9 rad
30 deg = pi/6 rad
120 deg = pi/3 rad
a) shift 2pi/9 units left, 7 units down
b) shift pi/6 units left, 8 units down
c) shift pi/3 units left, 3 units up
W = Fd = (8 * 9.8) * 6 = 470.4 N.
(my physics is still a bit rusty, but this is what i can come up with for now)
