kitty<3

First find the slope of the line, which uses the formula: 

$${\frac{\left({\mathtt{y2}}{\mathtt{\,-\,}}{\mathtt{y1}}\right)}{\left({\mathtt{x2}}{\mathtt{\,-\,}}{\mathtt{x1}}\right)}}$$

= $${\frac{\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{4}}\right)}{\left({\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)}}$$

= -3/6

=-1/2

Then plug in a point and the slope, $${\mathtt{m}}$$, into the point-slope formula:

$$\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{y1}}\right) = {m}{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{x1}}\right)}$$

$$\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{4}}\right) = {\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)\right)$$

Move the -4 to the right side:

$${\mathtt{y}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}$$

Simplify:

$${\mathtt{y}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}$$

1.5 is the same as 1 and one-half.

One-half is 1/2, and 1 is 2/2.

Therefore, the fraction would be 1/2 + 2/2,

  = 3/2.

On the top right corner of the Calculator, there is a gray botton labeled "Scientific." Click on it, then scroll down to "Fractions."

2/5 x = -8/15

Divide both sides by (2/5) to isolate x: 

x = (-8/15) / (2/5)

$${\frac{{\mathtt{\,-\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{15}}}}\right)}{\left({\frac{{\mathtt{2}}}{{\mathtt{5}}}}\right)}} = {\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{3}}}} = -{\mathtt{1.333\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

x = -4/3 

The decimal 0.175 is the same as 175/1000.

Simplify the fraction by dividing both the numerator and the denominator by their greatest common factor, 25:

$${\frac{{\mathtt{175}}}{{\mathtt{1\,000}}}} = {\frac{{\mathtt{7}}}{{\mathtt{40}}}}$$

Enter this into the website calculator with the correct parentheses. http://web2.0calc.com/

Assuming you meant negative six and one-half divided by negative two-thirds:  (-6 + 1/2) / (-2/3)

$${\frac{\left({\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)}{{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}} = {\frac{{\mathtt{33}}}{{\mathtt{4}}}} = {\mathtt{8.25}}$$

Subtracting a negative number is the same as adding the correlating positive number.

So 5 - (-8) is the same as 5 + 8.

I would be happy to assist you further if you need more help, but I believe you can take it from there:)

@ MAB25MAB: If 17.27 were the diameter, your answer would be correct.

However, Circumference is pi * the diameter, not twice the radius. 

$${\mathtt{C}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{d}}$$

Substitute in 17.27 for C:

$${\mathtt{17.27}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{d}}$$

$${\frac{{\mathtt{17.27}}}{{\mathtt{\pi}}}} = {\mathtt{d}}$$

$${\frac{{\mathtt{17.27}}}{{\mathtt{\pi}}}} = {\mathtt{5.497\: \!211\: \!734\: \!394\: \!064\: \!9}}$$

d = 5.497

Radius is half of the diameter:

$${\mathtt{r}} = {\frac{{\mathtt{d}}}{{\mathtt{2}}}}$$

$${\mathtt{r}} = {\frac{{\mathtt{5.497}}}{{\mathtt{2}}}} \Rightarrow {\mathtt{r}} = {\mathtt{2.748\: \!5}}$$

The radius is approximately 2.75 inches.

Enter this into the calculator and hope it's the answer to your rather wordy question:)

4/5 + (3/5 * 7/18) -0.2

$${\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\frac{{\mathtt{3}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{7}}}{{\mathtt{18}}}}\right){\mathtt{\,-\,}}{\mathtt{0.2}} = {\frac{{\mathtt{5}}}{{\mathtt{6}}}} = {\mathtt{0.833\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

Tu dijiste "el mismo perímetro que el rectangulo". Es rectangulo, o triangulo?

Si es el triangulo:

El triangulo tiene un lado 15 cm y uma diagonal 25 cm. Use el teorema de Pitágoras:

$${{\mathtt{a}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

Entonces:

$${{\mathtt{15}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {{\mathtt{25}}}^{{\mathtt{2}}}$$

$${\mathtt{225}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{b}}}^{{\mathtt{2}}} = {\mathtt{625}}$$

$${{\mathtt{b}}}^{{\mathtt{2}}} = {\mathtt{625}}{\mathtt{\,-\,}}{\mathtt{225}}$$

$${{\mathtt{b}}}^{{\mathtt{2}}} = {\mathtt{400}}$$

$${\mathtt{b}} = {\mathtt{20}}{cm}$$

Entonces, el perímetro del triangulo es:

$${\mathtt{P}} = {\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\mathtt{c}}$$

$${\mathtt{P}} = {\mathtt{15}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}{\mathtt{\,\small\textbf+\,}}{\mathtt{25}}$$

$${\mathtt{P}} = {\mathtt{60}}{cm}$$

Entonces, el perímetro del cuadrado es 60 cm, tambien.

El lado del cuadrado es 60/4 = 15

Finalmente, el área del cuadrado es 15 * 15, = 225cm.